sin a + cos a
Искусственно вводим дополнительный угол:
√2(1/√2sin a + 1/√2cos a) = √2sin(a+π/4)
-1 <= sin(a+π/4) <= 1|•√2
-√2 <= √2sin(a+π/4) <= √2
Ответ: min = -√2, max = √2
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sin a + cos a
Искусственно вводим дополнительный угол:
√2(1/√2sin a + 1/√2cos a) = √2sin(a+π/4)
-1 <= sin(a+π/4) <= 1|•√2
-√2 <= √2sin(a+π/4) <= √2
Ответ: min = -√2, max = √2