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maksim4k23
@maksim4k23
July 2022
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НАЙТИ НАИБОЛЬШЕЕ И НАИМЕНЬШЕЕ ЗНАЧЕНИЕ ФУНКЦИИ НА ОТРЕЗКЕ
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sedinalana
Verified answer
F`(x)=(2x³-6x-2x³+2x)/(x²-3)²=-4x/(x²-3)²=0
x=0∈[-1/2;1/2]
f(-1/2)=f(1/2)=(1/4-1):(1/4-3)=-3/4:(-11/4)=3/4*4/11=3/11-наим
f(0)=1/3 наиб
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maksim4k23
"(2x³-6x-2x³+2x)/(x²-3)²=-4x/(x²-3)²=0" откуда это все?
sedinalana
Как от куда? из производной
maksim4k23
2⋅x⋅(x^2+1)−(x^2−1)⋅2⋅x/(x^2+1)^2 - вот такая производная получается, нет?
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Answers & Comments
Verified answer
F`(x)=(2x³-6x-2x³+2x)/(x²-3)²=-4x/(x²-3)²=0x=0∈[-1/2;1/2]
f(-1/2)=f(1/2)=(1/4-1):(1/4-3)=-3/4:(-11/4)=3/4*4/11=3/11-наим
f(0)=1/3 наиб