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ast127
@ast127
August 2022
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Найти наибольшее значение выражения. Суть задания изложена в фото.
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sedinalana
Verified answer
Sin²a+cos²a=1
tg²a+1=1/cos²a
4*(tg²a+sin²a+cos²a)*cos^4a=4*(tg²a+1)*cos^4a=4*1/cos²a ^cos^4a=4cos²a
-1≤cosa≤1
0≤cos²a≤1
0≤4cos²a≤4
наибольшее значение 4
2 votes
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Answers & Comments
Verified answer
Sin²a+cos²a=1tg²a+1=1/cos²a
4*(tg²a+sin²a+cos²a)*cos^4a=4*(tg²a+1)*cos^4a=4*1/cos²a ^cos^4a=4cos²a
-1≤cosa≤1
0≤cos²a≤1
0≤4cos²a≤4
наибольшее значение 4