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savelevaelza
@savelevaelza
July 2022
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Найти наименьшее значение функции y=x^2-18x+3
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Semand21
Y=x^2-18x+3=(y-9)^2-78 т.к квадрат минимум 0 следовательно мин знач будет 78
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savelevaelza
А не -78?
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