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vladforgt
@vladforgt
July 2022
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Найти объем раствора CuSO4 Cн=0,1 н, содержащий 8г соли.
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SashaB11
Verified answer
Мне удобно искать через молярную конц. Cm = Cn÷z. z(CuSO4) = 2. Cn = 0,1÷2 = 0,05 М.
Дано:
См = 0,05 моль/л
m(CuSO4) = 8 г
Найти:
Vр-ра
Решение:
Vp-pa = n(CuSO4)÷Cm
n(CuSO4) = m÷Mr
Mr(CuSO4) = 63,5+32+64 = 159,5 г/моль
n(CuSO4) = 8÷159,5 = 0,05 моль
Vp-pa = 0,05÷0,05 = 1 л
Ответ: Vр-ра = 1л
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Answers & Comments
Verified answer
Мне удобно искать через молярную конц. Cm = Cn÷z. z(CuSO4) = 2. Cn = 0,1÷2 = 0,05 М.Дано:
См = 0,05 моль/л
m(CuSO4) = 8 г
Найти:
Vр-ра
Решение:
Vp-pa = n(CuSO4)÷Cm
n(CuSO4) = m÷Mr
Mr(CuSO4) = 63,5+32+64 = 159,5 г/моль
n(CuSO4) = 8÷159,5 = 0,05 моль
Vp-pa = 0,05÷0,05 = 1 л
Ответ: Vр-ра = 1л