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SashaVasileva1999
@SashaVasileva1999
September 2021
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Найти обл. определения выражения.
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sangers1959
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√(3-2x-x²)
ОДЗ:
3-2x-x²≥0 I*(-1)
x²+2x-3≤0 D=16
x₁=3 x₂=-1
(x-3)(x+1)≤0
-∞_____+____-1_____-______3______+_____+∞
x∈[-1;3].
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Answers & Comments
Verified answer
√(3-2x-x²)ОДЗ:
3-2x-x²≥0 I*(-1)
x²+2x-3≤0 D=16
x₁=3 x₂=-1
(x-3)(x+1)≤0
-∞_____+____-1_____-______3______+_____+∞
x∈[-1;3].