Найти область определения функции: (Фото). Created by VladF43. algebra-ru

Подкоренное выражение не отрицательноЗнаменатель не равен нулюПолучаем системуРешая ее получаем ответ: {-1;0} {1;3) (3;+беск) sedinalanasedinalana{x³-x≥0⇒x(x-1)(x+1)≥0⇒-1≤x≤0 U x≥1{x-3≠0⇒x≠3 _ + _ +----------------[-1]-------------[0]---------------[1]-----------------(3)----------x∈[-1;0] U [1;3) U (3;∞)Новые вопросы в АлгебраДАЮ 30 балів!!!!система рівняння графічнах-2у=1у-х=-2 Алгебра ДПА 9 класс 2 вариант 1.7Алгебра Мерзляк ДПА 9 класс 1.9 1 вариантАлгебра Мерзляк ДПА 9 классДопоможітьбудь ласка Знайдіть суму 100 перших членів послідовності аn, якщо ат = 2n+1Варіанти відповідей1020020400120001020a1=-5; d=6. Скільки треба взяти членів прогресії, щоб їх сума дорівнювала 35?Варіанти відповідей25730Помогите пожайлуста даю 70 балов!!!Верно ли,что если сумма a² + b²(a и b натуральные)делятся на 11,то числа a и b делятся на 11?Срочно с решениемПЛИСПредыдущийСледующийВместе мы знаем большеЭтот сайт использует cookies Политика Cookies . 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Найти область определения функции: (Фото)...

VladF43 @VladF43

July 2022 1 19 Report

Найти область определения функции:
(Фото)

Answers & Comments

Алкадиеныч

Verified answer

Подкоренное выражение не отрицательно
Знаменатель не равен нулю
Получаем систему
$\left \{ {{x((x-1)(x+1)) \geq 0} \atop {x \neq 3}} \right.$
Решая ее получаем ответ: {-1;0} {1;3) (3;+беск)

sedinalanasedinalana

{x³-x≥0⇒x(x-1)(x+1)≥0⇒-1≤x≤0 U x≥1
{x-3≠0⇒x≠3
_ + _ +
----------------[-1]-------------[0]---------------[1]-----------------(3)----------
x∈[-1;0] U [1;3) U (3;∞)