Найти область определения функции
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Ответ:

\dfrac{x-3}{2x-9}-\dfrac{x}{\sqrt{3x}+15}\\\\\\OOF:\ \ \left\{\begin{array}{l}2x-9\ne 0\\\sqrt{3x}+15\ne 0\\3x\geq 0\end{array}\right\ \ \left\{\begin{array}{l}2x\ne 9\\\sqrt{3x}\ne -15\\x\geq 0\end{array}\right\ \ \left\{\begin{array}{l}x\ne 4,5\\x\in R\\x\geq 0\end{array}\right\ \ \ \Rightarrow \\\\\\x\in D(y)=[\ 0\ ;4,5\ )\cup (\ 4,5\ ;+\infty \, )

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