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YuliaShckumat
@YuliaShckumat
July 2022
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найти область определения функции
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sedinalana
4-9/(x+1)+1/(x-3)≥0
(4x²-8x-12-9x+27+x+1)/(x+1)(x-3)≥0
(4x²-16x+16)/(x+1)9x-3)≥0
4(x²-4x+4)/(x+1)(x-3)≥0
4(x-2)²/(x+1)(x-3)≥0
x=2 x=-1 x=3
+ _ _ +
--------(-1)----------[2]----------(3)---------
x∈(-∞;-1) U (3;∞) U{2}
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Answers & Comments
(4x²-8x-12-9x+27+x+1)/(x+1)(x-3)≥0
(4x²-16x+16)/(x+1)9x-3)≥0
4(x²-4x+4)/(x+1)(x-3)≥0
4(x-2)²/(x+1)(x-3)≥0
x=2 x=-1 x=3
+ _ _ +
--------(-1)----------[2]----------(3)---------
x∈(-∞;-1) U (3;∞) U{2}