Найти область определения Нужен не просто ответ, а полное решение, пожалуйста. Created by ruserenarda. algebra-ru

1)(x²-9)/(16x²-8x+1)>0(x-3)(x+3)/(4x-1)²>0(4x-1)²>0;=>x€(-oo;1/4)U(1/4;+oo)(x-3)(x+3)>0;=>x€(-oo;-3)U(3;+oo)__-3_______1/4________3____=>x€(-oo;-3)U(3;+oo)2){3-x>0;x<3 {3-x≠1;x≠4=>x<33){x<3 {x€(-oo;-3)U(3;+oo);=>x€(-oo;-3)Новые вопросы в АлгебраРозв'язати нерівність. У відповідь записати добуток усіх цілих чисел, які не є розв'язками нерівності .1.1/x² - 3x + 2 <= 1/22.2 + 1/x - 3 + x - 3/…x + 2)<= 1/(x - 3)(x + 2)3.2/3x + 7 <= 1/x + 3 - 1/x + 14.x - 8/x² - 5x + 4 > 2/x + 1СРОЧНО ОЧЕНЬ ЛЁГКОЕ УПРАЖНЕНИЕ12⁹+13⁹ решитьвот можно бистрее решить2)4x-1=7x+83)2(3x+2)-3(x-1)=134)4(5x-1)-2(3-2x)=10Допоможіть, буду вдячна!!з поясненням, будь ласкадопоможіть будь ласкапожалуйста, помогите, просто умоляю, всю голову сломалаПомогите с интеграломПомогите с интегралом пожалуйстаЗнайдіть розв’язок нерівності: 3х − 6 < 3.ПредыдущийСледующийВместе мы знаем большеЭтот сайт использует cookies Политика Cookies . 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Найти область определения Нужен не просто ответ, а полное решение, пожалуйста...

ruserenarda @ruserenarda

July 2022 1 1 Report

Найти область определения
Нужен не просто ответ, а полное решение, пожалуйста

Answers & Comments

армения20171

Verified answer

1)(x²-9)/(16x²-8x+1)>0
(x-3)(x+3)/(4x-1)²>0
(4x-1)²>0;=>x€(-oo;1/4)U(1/4;+oo)
(x-3)(x+3)>0;=>x€(-oo;-3)U(3;+oo)

__-3_______1/4________3____
=>x€(-oo;-3)U(3;+oo)

2){3-x>0;x<3
{3-x≠1;x≠4
=>x<3

3){x<3
{x€(-oo;-3)U(3;+oo);=>x€(-oo;-3)