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Lika32
@Lika32
July 2022
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Найти область определения выражения
все под корнем √(x^2+6x)^-1
Помогите!!!!!
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natali3221
(√(x²+6x)^-1
x²+6x>0
x(x+6)>0
+++(-6)-----0+++
x∈(-∞ -6)∪(0 ∞)
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Answers & Comments
x²+6x>0
x(x+6)>0
+++(-6)-----0+++
x∈(-∞ -6)∪(0 ∞)