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tonko2001
@tonko2001
July 2022
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Найти область определения выражения
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wejde
Verified answer
Y=(√x-2)/(sin²x-sinx-2)
D(y):
1) x-2≥0, x≥2
2) sin²x-sinx-2≠0
sinx=t, t∈[-1;1]
t²-t-2=0
D=(-1)²-4*(-2)=9
t=(1+3)/2=4/2=2 - посторонний корень, т.к. t∈[-1;1]
t=(1-3)/2=-2/2=-1
sinx=-1
x=-π/2+2πn, n∈Z
Ответ: x∈[2;+∞) U x≠-π/2+2πn, n∈Z
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Answers & Comments
Verified answer
Y=(√x-2)/(sin²x-sinx-2)D(y):
1) x-2≥0, x≥2
2) sin²x-sinx-2≠0
sinx=t, t∈[-1;1]
t²-t-2=0
D=(-1)²-4*(-2)=9
t=(1+3)/2=4/2=2 - посторонний корень, т.к. t∈[-1;1]
t=(1-3)/2=-2/2=-1
sinx=-1
x=-π/2+2πn, n∈Z
Ответ: x∈[2;+∞) U x≠-π/2+2πn, n∈Z