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zaharovDen
@zaharovDen
July 2022
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Найти общее решение дифференциального уравнения.y''+2y'+10y=0
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andrisd
Verified answer
Y''+2y'+10y=0
Ce^(kx)(k²+2k+10)=0
k²+2k+10=0
D=4-4*(10)=-36
k1=(-2+i√36)/2=-1+3i
k2=-1-3i
y(x)=C1e^(x(-1+3i))+C2e^(x(-1-3i))
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Answers & Comments
Verified answer
Y''+2y'+10y=0Ce^(kx)(k²+2k+10)=0
k²+2k+10=0
D=4-4*(10)=-36
k1=(-2+i√36)/2=-1+3i
k2=-1-3i
y(x)=C1e^(x(-1+3i))+C2e^(x(-1-3i))