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масяня38
@масяня38
November 2021
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найти определенный интеграл
сверху 2 снизу- 1;(x^2-6x+9)dx
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sangers1959
Verified answer
Int I₋₁²(x²-6x+9)=x³/3-3x²+9x I₋₁²=
=1³/3-3*1²+9*1-(-2)³/3+3*(-2)²-9*(-2)=1/3-3+9+8/3+12-9=12.
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Answers & Comments
Verified answer
Int I₋₁²(x²-6x+9)=x³/3-3x²+9x I₋₁²==1³/3-3*1²+9*1-(-2)³/3+3*(-2)²-9*(-2)=1/3-3+9+8/3+12-9=12.