Найти первообразную 2\!х (два корня из х)
F(2√x)=2F(√x)=2F(x^1/2)=2*(x^3/2 / (3/2) = 2* 2/3 * x^3/2 = 4/3 * x^3/2
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F(2√x)=2F(√x)=2F(x^1/2)=2*(x^3/2 / (3/2) = 2* 2/3 * x^3/2 = 4/3 * x^3/2