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Кнопка56
@Кнопка56
August 2021
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Найти площадь криволинейной трапеции:
2h
∫ cos 2 xdx
-h
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rskopov
Решение:
F(x)=sin2x/2
F(2h)=1/2sin4h
F(-h)=1/2sin(-h)=-1/2sinh
S=F(2h)-F(-h)=1/2(sin4h+sinh)=sin5h/2cos3h/2.
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Answers & Comments
F(x)=sin2x/2
F(2h)=1/2sin4h
F(-h)=1/2sin(-h)=-1/2sinh
S=F(2h)-F(-h)=1/2(sin4h+sinh)=sin5h/2cos3h/2.