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lenaclenina
@lenaclenina
February 2022
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Найти площадь поверхности прямоугольного параллелепипеда с измерениями 4см, 5см, 6см.
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lancerjr
S=2(ab+bc+ac)=2(20+30+24)=148 см
3 votes
Thanks 1
stas0107
Sпов.=2×(4×5+5×6+4×6)=
2×(20+30+24)=2×74=148(квадратных см)
4 votes
Thanks 3
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Answers & Comments
2×(20+30+24)=2×74=148(квадратных см)