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andreymetal
@andreymetal
October 2021
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Найти площадь треугольника ABC
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армения20171
А=2R•sin60°=2•4•√3/2=4√3
S=1/2*a*a*sin60°=1/2*(4√3)²*√3/2=
1/2*16*3*√3/2=12√3
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Answers & Comments
S=1/2*a*a*sin60°=1/2*(4√3)²*√3/2=
1/2*16*3*√3/2=12√3