AB = √(0+9+1) = √10
BC = √(4+1+9) = √14
AC = √(4 + 16 + 4) = √24
S = √(p(p-a)(p-b)(p-c)) = √((√10+√14+√24)(√10+√14-√24)(√24+√10-√14)(√24-√10+√14)/16) = √140 = 2√35
Ответ: 2√35
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Verified answer
AB = √(0+9+1) = √10
BC = √(4+1+9) = √14
AC = √(4 + 16 + 4) = √24
S = √(p(p-a)(p-b)(p-c)) = √((√10+√14+√24)(√10+√14-√24)(√24+√10-√14)(√24-√10+√14)/16) = √140 = 2√35
Ответ: 2√35