Ответ:
Объяснение:
q=3*10^5 Кл r=0.2 м
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E=k*q/r²=9*10^9*3*10^-5/0.04=6.75*10^6 В/м
φ=k*q/r=9*10^9*3*10^-5/0.2=1.35*10^6 B
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Ответ:
Объяснение:
q=3*10^5 Кл r=0.2 м
===
E=k*q/r²=9*10^9*3*10^-5/0.04=6.75*10^6 В/м
φ=k*q/r=9*10^9*3*10^-5/0.2=1.35*10^6 B
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