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Humayni
@Humayni
June 2022
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Найти предел сррчно пожжжжж
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Vas61
Используем первое правило Лопиталя
если lim(x³+x+2)=0 и lim(x³+1)=0 lim(x³+x+2/x³+1)=lim(x³+x+2)'/(x³+1)'=
ˣ→⁻¹ ˣ→⁻¹ ˣ→⁻¹ ˣ→⁻¹
lim(3x²+1)/3x²=(3+1)/3=4/3
ˣ→⁻¹
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Humayni
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Answers & Comments
если lim(x³+x+2)=0 и lim(x³+1)=0 lim(x³+x+2/x³+1)=lim(x³+x+2)'/(x³+1)'=
ˣ→⁻¹ ˣ→⁻¹ ˣ→⁻¹ ˣ→⁻¹
lim(3x²+1)/3x²=(3+1)/3=4/3
ˣ→⁻¹