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Marisca
@Marisca
September 2021
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найти производную функции
Ctgx-tgx
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snoww97
(ctg x)'= -1/sin²x
(tg x)' = 1/cos²x
ctg x- tg x= -1/sin²x -1/cos²x = -(cos²x+sin²x)/sin²x*cos²x= -1/sin²x*cos²x
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Answers & Comments
(tg x)' = 1/cos²x
ctg x- tg x= -1/sin²x -1/cos²x = -(cos²x+sin²x)/sin²x*cos²x= -1/sin²x*cos²x