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WinsVend
@WinsVend
July 2022
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Найти производную функции:
f(x) = xsin(2x+1)
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gfhfgughj
(u*v)'=u'*v+u*v'
(sin(u))'=cos(u)*u'
f'(x)=1*sin(2x+1)+x*2cos(2x+1)= sin(2x+1)+ 2xcos(2x+1)
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Бе3ума
Sin(2x+1)+2xcos(2x+1)
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Answers & Comments
(sin(u))'=cos(u)*u'
f'(x)=1*sin(2x+1)+x*2cos(2x+1)= sin(2x+1)+ 2xcos(2x+1)