y'=(x³)'*ln(x)+x³*(ln(x))'= 3x²*ln(x)+x³/x= 3x²*ln(x)+x²= x²(3ln(x)+1)
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y'=(x³)'*ln(x)+x³*(ln(x))'= 3x²*ln(x)+x³/x= 3x²*ln(x)+x²= x²(3ln(x)+1)