найти производную функции у=(х^2-3x+1)^7
y'=((x^2-3x+1)^7)'=7(x^2-3x+1)^6*(x^2-3x+1)'=7(x^2-3x+1)^6*(2x-3)=14x-21(x^2-3x+1)
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y'=((x^2-3x+1)^7)'=7(x^2-3x+1)^6*(x^2-3x+1)'=7(x^2-3x+1)^6*(2x-3)=14x-21(x^2-3x+1)