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pronn
@pronn
June 2022
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Найти производную функции
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Юлечka
F'=(sin x^3/2)'-(cos^2 20x/10sin10x)'=Cos x^3/2*3/2x^1/2-((cos^2 20x)'*10sin10x-Cos^2 20x*(10sin10x)')/100Sin^2 10x=3/2*x^1/2*Cosx^3/2-(-40Cos20xSin20x*10sin10x-Cos^2 20x*100Cos10x)/100sin^2 10x=3/2*x^1/2*Cosx^3/2+(4Cos20xSin20xsin10x+Cos^2 20xCos10x)/sin^2 10x
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pronn
Спасибо большое, можете еще помочь?
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