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HelpMePlsGuys
@HelpMePlsGuys
March 2022
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найти производную функции
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Lesben
F(x)=cotg(2xˇ2-V2)
f´(x)= -1/sinˇ2(2xˇ2-V2) . (2xˇ2-V2)´=
=-1/sinˇ2(2xˇ2-V2) .(4x)=-4x/sinˇ2(2xˇ2-V2)
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Answers & Comments
f´(x)= -1/sinˇ2(2xˇ2-V2) . (2xˇ2-V2)´=
=-1/sinˇ2(2xˇ2-V2) .(4x)=-4x/sinˇ2(2xˇ2-V2)