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vikusja1ove312
@vikusja1ove312
July 2022
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Найти производную y=arcsinx^2
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SHINIGAMI227
Y=x²arcsinx
(uv)/=u'v+v'u
y'=(x²)'arcsinx+(arcsinx)'x²=2xarcsinx+x²/√(1-x²)
4 votes
Thanks 4
vikusja1ove312
Спасибо большое
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Answers & Comments
(uv)/=u'v+v'u
y'=(x²)'arcsinx+(arcsinx)'x²=2xarcsinx+x²/√(1-x²)