Ответ:
f'(x)=-sin(2x)
Объяснение:
f'(x)=(cos^2 x-1)'=2×cos x × (cos x)'-0=2cos x × (-sin x)=-2sin x × cos x=- sin(2x)
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Verified answer
Ответ:
f'(x)=-sin(2x)
Объяснение:
f'(x)=(cos^2 x-1)'=2×cos x × (cos x)'-0=2cos x × (-sin x)=-2sin x × cos x=- sin(2x)
Verified answer
Ответ: