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GRUZZLY
@GRUZZLY
July 2022
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Найти разность z2-z1 b и частное z2\z1, если известно что z1=2+2i,z2=1-i.
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sedinalana
Verified answer
Z2-z1=1-i-2-2i=-1-3i
z2/z1=(1-i)/(2+2i)=(1-i)(2-2i)/[(2+2i)(2-2i)]=
=(2-2i-2i-2)/(4+4)=(-4i/8=-1/2*i
1 votes
Thanks 1
007Укроп228
1)z2-z1=(1-i)-(2-2i)=-1-3i
2)z2\z1=(1-i)\(2-2i)=(1-i)(2-2i)\(2+2i)(2-2i)=(2-2i-2i-2)\(4+4)=-0,5i
2 votes
Thanks 1
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Verified answer
Z2-z1=1-i-2-2i=-1-3iz2/z1=(1-i)/(2+2i)=(1-i)(2-2i)/[(2+2i)(2-2i)]=
=(2-2i-2i-2)/(4+4)=(-4i/8=-1/2*i
2)z2\z1=(1-i)\(2-2i)=(1-i)(2-2i)\(2+2i)(2-2i)=(2-2i-2i-2)\(4+4)=-0,5i