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gorynych777
@gorynych777
October 2021
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Найти силу взаимодействия двух пластин +фото
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solvo
S=2 дм^2= 2*10^-2 м^2, ε=2,1, d=0,004 м, U=150В. F-?
E=q/(2ε0εS),
F=qE = q^2/(2ε0εS),
q=CU=ε0εSU/d,
F=(ε0εSU)^2/(2ε0εS*d^2) =ε0εS*U^2/(2d^2).
F=8,85*10^-12*2,1*2*10^-2*225*10^2/(2*16*10^-6)=261,4*10^-6 Н=0,26*10^-3Н.
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Answers & Comments
E=q/(2ε0εS),
F=qE = q^2/(2ε0εS),
q=CU=ε0εSU/d,
F=(ε0εSU)^2/(2ε0εS*d^2) =ε0εS*U^2/(2d^2).
F=8,85*10^-12*2,1*2*10^-2*225*10^2/(2*16*10^-6)=261,4*10^-6 Н=0,26*10^-3Н.