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nastyadobychina
@nastyadobychina
November 2021
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найти sin a cos a ctg a , если tg a-корень из 3 и a пренадлежит (пи до 3пи вторых)
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oganesbagoyan
Verified answer
Tqα =√3 ; α∈(π ; 3π/2).
--------------------------------
sinα -->?
cosα--> ?
ctqα --> ?
ctqα =1/tqα =1/√3.
1 + tq²α =1/cos²α ⇒ cosα= - 1/(√1+tq²α) (т.к. α∈(π ; 3π/2).
cosα= - 1/2 .
sinα =cosα*tqα = -√3/2.
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Answers & Comments
Verified answer
Tqα =√3 ; α∈(π ; 3π/2).--------------------------------
sinα -->?
cosα--> ?
ctqα --> ?
ctqα =1/tqα =1/√3.
1 + tq²α =1/cos²α ⇒ cosα= - 1/(√1+tq²α) (т.к. α∈(π ; 3π/2).
cosα= - 1/2 .
sinα =cosα*tqα = -√3/2.