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abra123
@abra123
July 2022
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найти суму первых шести членов арифметической прогрессии если a1+a5= -4
a4*a2=6
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Удачник66
Verified answer
Арифметическая прогрессия
a2 = a1 + d; a4 = a1 + 3d; a5 = a1 + 4d
Система
{ a1 + a1 + 4d = 2a1 + 4d = -4; a1 + 2d = -2
{ (a1 + d)(a1 + 3d) = 6
Из 1 уравнения
a1 + d = -2 - d
a1 + 3d = -2 + d
-(2 + d)(-2 + d) = 6
(d + 2)(d - 2) = -6
d^2 - 4 = -6
d^2 = -2
Решений нет
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Answers & Comments
Verified answer
Арифметическая прогрессияa2 = a1 + d; a4 = a1 + 3d; a5 = a1 + 4d
Система
{ a1 + a1 + 4d = 2a1 + 4d = -4; a1 + 2d = -2
{ (a1 + d)(a1 + 3d) = 6
Из 1 уравнения
a1 + d = -2 - d
a1 + 3d = -2 + d
-(2 + d)(-2 + d) = 6
(d + 2)(d - 2) = -6
d^2 - 4 = -6
d^2 = -2
Решений нет