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CrazyTed1
@CrazyTed1
July 2022
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Найти точки экстремума функции
1)у=3-5х-х^2
2)у=4х^2-6х-7
3)у=-3х^2-12х+50
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cdrrtv
1)3-5х-х2
2)у=4х2-6х-7
3)у=-3х2-12х+50
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Answers & Comments
2)у=4х2-6х-7
3)у=-3х2-12х+50