y=∫sinxdx=-cosx+C
1/2=-cos(π/3)+C
1/2+1/2=C
C=1
y=-cosx+1 - искомое уравнение
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y=∫sinxdx=-cosx+C
1/2=-cos(π/3)+C
1/2+1/2=C
C=1
y=-cosx+1 - искомое уравнение