Verified answer

3^2+log (9 )16 = 9 + log (3^2) 2^4 = 9+ 4*1/2* log (3) 2=9 + 2* log(3) 2

3^(2+log (9 )16)=3^2*3^log (3^2) 2^4)= ( посвойству a^(b+c)=a^b*a^c и a^ log (a) b=b)=  9* 3^(1/2*4*log (3)2)=9* 3^log (3) 4 = 9*4=36