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ulker18
@ulker18
July 2022
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Найти значение произвольную функцию:y=(x+1)(x-2)в точке х=3
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mionkaf1
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matilda17562
Решение:
1) у = (х + 1)·(х - 2) = х² - 2х + х - 2 = х² - х - 2
2) у` = (х² - х - 2)` = 2x - 1 - 0 = 2x - 1.
3) у` (3) = 2··3 - 1 = 6 - 1 = 5
Ответ: 5.
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Answers & Comments
1) у = (х + 1)·(х - 2) = х² - 2х + х - 2 = х² - х - 2
2) у` = (х² - х - 2)` = 2x - 1 - 0 = 2x - 1.
3) у` (3) = 2··3 - 1 = 6 - 1 = 5
Ответ: 5.