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anddevegor
@anddevegor
July 2022
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найти значение выражения (4Х+3у+1)2 +(Х+5У-4)2
2- это вторая степень
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байда2
16x^2+9y^2+1+x^2+25y^2-
-16=17x^2+34y^2-15
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-16=17x^2+34y^2-15