Написать реакции преобразования
CU ->CUO->CUCl2->CU(OH)2->CUO->CU
2cu+o2=2cuo
CuO + 2HCl= CuCl2 + H2O
Ca(OH)2 + CuCl2 → Cu(OH)2↓ + CaCl2 Cu(OH)2 = CuO + H2O
CuO+CO=Cu+CO2
Cu → CuO → CuCl2 → Cu(OH)2 → CuO → Cu 2Cu + O2 = 2CuOCuO + 2HCl(разб.) = CuCl2 + H2OCa(OH)2 + CuCl2 → Cu(OH)2↓ + CaCl2Cu(OH)2 = CuO + H2OCuO + H2 = Cu + H2O
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
2cu+o2=2cuo
CuO + 2HCl= CuCl2 + H2O
Ca(OH)2 + CuCl2 → Cu(OH)2↓ + CaCl2
Cu(OH)2 = CuO + H2O
CuO+CO=Cu+CO2
Cu → CuO → CuCl2 → Cu(OH)2 → CuO → Cu
2Cu + O2 = 2CuO
CuO + 2HCl(разб.) = CuCl2 + H2O
Ca(OH)2 + CuCl2 → Cu(OH)2↓ + CaCl2
Cu(OH)2 = CuO + H2O
CuO + H2 = Cu + H2O