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LaStrega
@LaStrega
July 2022
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Написать реакции превращения al->al2o3->al(oh)3-> две соли alcl3 и na[al(oh)3]
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Verified answer
4Al + 3O₂ = 2Ai₂O₃
l2o3->al(oh)3-можно получить косвенным путем
Al₂O₃ + 6HCl = 2
AlCl₃
+ 3H₂O, \\AlCl₃ + 3NaOH = Al(OH)₃ + 3NaCl
Al(OH)₃ + 3HCl =
AlCl₃
+ 3NaCl
Al(OH)₃ + NaOH = Na[Al(OH)₄]
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Answers & Comments
Verified answer
4Al + 3O₂ = 2Ai₂O₃l2o3->al(oh)3-можно получить косвенным путем
Al₂O₃ + 6HCl = 2AlCl₃ + 3H₂O, \\AlCl₃ + 3NaOH = Al(OH)₃ + 3NaCl
Al(OH)₃ + 3HCl = AlCl₃ + 3NaCl
Al(OH)₃ + NaOH = Na[Al(OH)₄]