Написать уравнения реакций в молекулярном и ионном виде: а) (CH3COO) 2Ca и НNO3 ...

July 2022 1 2 Report

Написать уравнения реакций в молекулярном и ионном виде: а) (CH3COO) 2Ca и НNO3 б) NaH2SbO3 и NaOH в) (ZnOH) 2SO4 и Н2SO4

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mrvladimir2

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(CH₃COO)₂Ca + 2HNO3 => Ca(NO₃)₂ + 4CO₂ + 4H₂O
2CH₃COO⁻+Ca²⁺ + 2H⁺+2NO₃⁻ = Ca²⁺+2NO₃ + 4CO₂ + 4H₂O
2CH₃COO⁻ + 2H⁺ = 4CO₂ + 4H₂O
CH₃COO⁻ + H⁺ = 2CO₂ +2H₂O

NaH₂SbO₃ + NaOH = Na₂HSbO₃+H₂O
Na⁺+H₂SbO₃⁻ + Na⁺+OH⁻ = 2Na + HSbO₃²⁻ + H₂O
H₂SbO₃⁻ + OH⁻ = HSbO₃²⁻ + H₂O

(ZnOH)₂SO₄ + H₂SO₄ = 2ZnSO₄ + 2H₂O
2ZnOH⁻ + SO₄²⁻+2H⁺+SO₄²⁻ = 2Zn²⁺+2SO₄²⁻ + 2H₂O
2ZnOH⁻ + 2H⁺ = 2Zn²⁺ + 2H₂O
ZnOH⁻ + H⁺ = Zn²⁺ + H₂O

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Sniper3000 September 2021 | 0 Ответы

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