1)
sin0°=0
tg0°=0
cos90°=0
ctg90°=0
a·0+b·0+c·0-b·0=0
2)
tg(π/4)=1
sin(π/4)=√2/2
tg0=0
ctg(π/4)=0
=a·1+2b·(√2/2)-3a·0-2a·1=√2·b-a
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Verified answer
1)
sin0°=0
tg0°=0
cos90°=0
ctg90°=0
a·0+b·0+c·0-b·0=0
2)
tg(π/4)=1
sin(π/4)=√2/2
tg0=0
ctg(π/4)=0
=a·1+2b·(√2/2)-3a·0-2a·1=√2·b-a