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marisha3797
@marisha3797
August 2022
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Напишите программу для нахождения первого члена последовательности e√n-100, большего чем 100
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oVokeck
#include <iostream>#include <math.h>
using namespace std;
int main(int argc, char* argv[]){ int e = 2.71; int count = 0; for(int n = 0;;n++) { count = e * sqrt(n) - 100; if(count > 100) { cout << "count = " << count; break; } } return 0;}
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using namespace std;
int main(int argc, char* argv[]){ int e = 2.71; int count = 0; for(int n = 0;;n++) { count = e * sqrt(n) - 100; if(count > 100) { cout << "count = " << count; break; } } return 0;}