напишите степень окисления
C+O2=CO2
4Al+3O2=2Al2O3
2Mg+2HCl=MgCl2+H2
C⁰+O₂⁰=C⁺⁴O₂⁻²
4Al°+3O₂°=2Al₂⁺³O₃⁻²
2Mg°+2H⁺¹Cl⁻¹=Mg⁺²Cl₂⁻¹+H₂°
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
C⁰+O₂⁰=C⁺⁴O₂⁻²
4Al°+3O₂°=2Al₂⁺³O₃⁻²
2Mg°+2H⁺¹Cl⁻¹=Mg⁺²Cl₂⁻¹+H₂°