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pskovbatruha
@pskovbatruha
August 2022
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Напишите уравнение касательной к графику функции f(x) = x3 - 2x2 + 1 в точке с абсциссой 2.
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akbotanurtoleu
Ответ:
f(x)=x^3-2x^2+1
!!!!!!!!!!!!!
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Ответ:
f(x)=x^3-2x^2+1
!!!!!!!!!!!!!