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TheNaik
@TheNaik
August 2022
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rskopov
Решение:
f'(x)=3x^2-6x+2
y-f(x0)=f'(x0)(x-x0)
f(1)=1-3+2+4=4
f'(1)=3-6+2=-1
y-4=-1(x-1)
y-4=-x+1
y=-x+5.
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Answers & Comments
f'(x)=3x^2-6x+2
y-f(x0)=f'(x0)(x-x0)
f(1)=1-3+2+4=4
f'(1)=3-6+2=-1
y-4=-1(x-1)
y-4=-x+1
y=-x+5.