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4evеr
@4evеr
July 2022
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Напишите уравнения в сокращенном ионном виде
1) CuSO₄+2NaOH → Cu(OH)₂+Na₂SO₄
2) Cu(OH)₂+2HCL → CuCL₂+2H₂O
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svetka1574
Verified answer
CuSO4 + 2NaOH -> Cu(OH)2↓ + Na2SO4
Cu(+2) + SO4(-2) + 2Na(+) + 2OH(-)-> Cu(OH)2↓ + 2Na(+) + SO4(-2)
Cu(+2)+ 2OH(-) -> Cu(OH)2↓
Cu(OH)2 + 2HCl -> CuCl2 + 2H2O
Cu(OH)2 + 2H(+) + 2Cl(-)-> Cu(+2) + 2Cl(-) + 2H2O
Cu(OH)2 + 2H(+)-> Cu(+2) + 2H2O
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Answers & Comments
Verified answer
CuSO4 + 2NaOH -> Cu(OH)2↓ + Na2SO4Cu(+2) + SO4(-2) + 2Na(+) + 2OH(-)-> Cu(OH)2↓ + 2Na(+) + SO4(-2)
Cu(+2)+ 2OH(-) -> Cu(OH)2↓
Cu(OH)2 + 2HCl -> CuCl2 + 2H2O
Cu(OH)2 + 2H(+) + 2Cl(-)-> Cu(+2) + 2Cl(-) + 2H2O
Cu(OH)2 + 2H(+)-> Cu(+2) + 2H2O