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-1≤sin t≤1,
-3≤3sin t≤3,
1≤3sin t+4≤7,
max=7;
(sin^ α - 2cos^ α)/(3sin α cos α - cos^ α)=sin^ α(1- 2ctg^ α)/(sin^ α(3ctg α - ctg^ α))=(1- 2*2^)/(3*2 - 2^)=-3,5;
-2≤2sin t≤2,
0≤2sin t+2≤4,
max=4
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Verified answer
-1≤sin t≤1,
-3≤3sin t≤3,
1≤3sin t+4≤7,
max=7;
(sin^ α - 2cos^ α)/(3sin α cos α - cos^ α)=sin^ α(1- 2ctg^ α)/(sin^ α(3ctg α - ctg^ α))=(1- 2*2^)/(3*2 - 2^)=-3,5;
-1≤sin t≤1,
-2≤2sin t≤2,
0≤2sin t+2≤4,
max=4