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Approaching2the0
@Approaching2the0
July 2022
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Не выполняя построения, найдите координаты точек пересечения графиков функций 5x+y=-1; xy=-6
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sedinalana
Verified answer
5x+y=-1
y=-5x-1
xy=-6
x(-5x-1)=-6
-5x²-x=-6
5x²+x-6=0
D=1+120=121
x1=(-1-11)/10=-1,2⇒y=-5*(-1,2)-1=6-1=5
x2=(-1+11)/10=1⇒y=-5*1-1=-6
(-1,2;5);(1;-6)
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Answers & Comments
Verified answer
5x+y=-1y=-5x-1
xy=-6
x(-5x-1)=-6
-5x²-x=-6
5x²+x-6=0
D=1+120=121
x1=(-1-11)/10=-1,2⇒y=-5*(-1,2)-1=6-1=5
x2=(-1+11)/10=1⇒y=-5*1-1=-6
(-1,2;5);(1;-6)