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MeriCati
@MeriCati
July 2022
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Не выполняя построения, найдите координаты точек пересечения пппараболы y = x^2 + 4 и прямой x + y = 6
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Анатоле
X^2 + 4 = 6 - x
x^2 + x - 2 = 0
D = 1+8 = 9
x1 = (-1+3)/2 = 1
x2 = (-1 -3)/2 = -2
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Answers & Comments
x^2 + x - 2 = 0
D = 1+8 = 9
x1 = (-1+3)/2 = 1
x2 = (-1 -3)/2 = -2